x^2-35x+66=0

Solution for x^2-35x+66=0 equation:

x^2-35x+66=0

a = 1; b = -35; c = +66;
Δ = b2-4ac
Δ = -352-4·1·66
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-31}{2*1}=\frac{4}{2}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+31}{2*1}=\frac{66}{2}
=33
$